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The slope of the tangent line to the curve y= 3x^3 at the point (-1,-3) is:?

The equation of this tangent line can be written in the form y=mx+b where m is:?
and where b is:?

1 answer

dy/dx = 9x^2
at (-1,-3) , dy/dx = 9(1) = 9

equation of tangent
y = 9x + b
but (-1,-3) lies on it,
-3 = 9(-1) + b
6 = b

y = 9x + 6 , m = 9 and b = 6
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