The sides of the equilateral triangle is 3x+2,2y-x and y+3 find x and y.and the perimeter of the triangle

Answer 1

well, since all the sides are the same length, we just have to solve

3x+2 = 2y-x
3x+2 = y+3

4x-2y = -2
3x-y = 1

Find x and y, and then you can find the perimeter.

Answer 2

i do not like the answer

Answer 3

i do not like the answer

Answer 4

i didnt get it

Answer 5

I dont understand

Answer 6

3x+2cm=2y-x cm
3x+2cm=y+3cm

3x+2cm=2y-x cm
Collect like terms
3x+x cm - 2y=-2cm
4x cm+2y=-2cm...(i)

3x+2cm=y+3cm
Collect like terms
3x-y=3cm-2cm
3x-y=1cm...(ii)

4x cm+2y= -2cm
3x-y=1cm

Multiply eqn(i) by 3 and multiply eqn(ii) by 4

12x+6y= -6cm
—
12x-4y= 4cm
10y=-10cm
Divide both sides by 10

10y/10=-10cm/10
y=-1cm

Put -1cm in eqn(ii)
3x-y=1cm
3x-(-1cm)=1cm
3x+1=1cm
Collect like terms
3x=1-1
3x=0
Divide both sides by 3
3x/3=3/3
x=0
So, x=0 and y=-1

Perimeter of the triangle=
(3x+2cm) + (2y-x)cm + (y+3cm)
=3(0)+2 + 2(-1)-0 + (-1)+3
=0+2 + (-2) + 2
=2-2+2
=2
That is my perimeter answer. Not sure if it's correct.

Answer 7

I am not sure if the answers are correct.

Answer 8

I do not think the answer is correct

Answer 9

I didn't understand the answer

Answer 10

2x-y=2

Answer 11

I am the one who ask the question

Answer 12

3x+2 = 2y-x
3x+2 = y+3

Collect like terms
4x-2y = -2 ---eqn1
3x-y = 1 ---eqn2

Using elimination method
Multiply (eqn 2) by 2

6x-2y = 2 ---eqn3
4x -2y = -2 ---eqn2
_______________
2x = 4
Divide both sides by the coefficient of x
x = 2

Then substitute (2 for x) in eqn 3
6(2)-2y = 2
12-2y = 2
-2y = 2-12
-2y = -10
Divide both sides by -2
y = 5

P= a+b+c
3x+2 = 8cm
2y-x = 8cm
y+3 = 8cm

Perimeter= 24cm

That's the correct answer

Answer 13

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