The shell’s trajectory curves downward because of gravity, so at the time t = 0.217 s

Question

the shell is below the straight line by some
vertical distance ∆h.
Find this distance ∆h in the absence of
air resistance. The acceleration of gravity is
9.8 m/s
2
.
Answer in units of m

Answer 1

∆h = (g/2)t^2

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