A cannon fires a 0.598 kg shell with initial velocity 10 m/s in the direction 46◦ above the horizontal.

Question

The shell’s trajectory curves downward be- cause of gravity, so at the time t = 0.53 s the shell is below the straight line by some verti- cal distance ∆h. Your task is to calculate the distance ∆h in the absence of air resistance.
On what does ∆h depend (besides g)?

Answer 1

Problem entirely vertical assuming your straight line is horizontal

Vi = 10 sin 46

v = Vi - g t

delta h = Vi t - (1/2) g t^2

Answer 2

That didn't answer the question