The sum of an infinite geometric progression is given by the formula:
S = a₁ / (1 - r)
where a₁ is the first term and r is the common ratio.
In this case, a₁ = 1 and r = 1/8.
Therefore, the sum of infinity of the sequence is:
S = 1 / (1 - 1/8) = 8/7
The second and fifth term of a G.P are 1 1/8 respectively.find the sum of infinity of the sequence
3 answers
Find the values of x for which 1/3(2x+7)-1/5(1-4x)_<4+x
X-2y+1_>0
-8x-y-2>0
X-2y+1_>0
-8x-y-2>0
AAAaannndd the bot gets it wrong yet again!
ar=1
ar^4 = 1/8
so r^3 = 1/8, making r = 1/2
so a = 2 and
S = a/(1-r) = 2/(1 - 1/2) = 4
Depending on the value of y, we get -5/17 < x < 4
I suspect you have left something out.
ar=1
ar^4 = 1/8
so r^3 = 1/8, making r = 1/2
so a = 2 and
S = a/(1-r) = 2/(1 - 1/2) = 4
Depending on the value of y, we get -5/17 < x < 4
I suspect you have left something out.
0 answers