The scale of a pitch is 1cm to 2.5m. If the length was drawn as 5cm, how long is the ground?

Answer 1

sketch a right-angled triangle representing your slope of 2.5/1
with a vertical of 5 and a horizontal of 2
then its hypotenuse is √29

In another similar triangle , let the "ground " be x
and its hypotenuse be 5
x /2 = √29/5
x = 2√29/5 = appr 2.154

in the first triangle the units were metres, in the second they were cm
In my equation, the units would cancel

Answer 2

Oooops .... My ratio should have been:
x/2 = 5/√29
x = 10/√29
x =1.8569

We could have used trig
from the slope of 2.5/1
tan P = 2.5/1
angle P = 68.1986°

now you want the base side
cos 68.1986 = x/5
x = 5cos68.1986 = appr 1.8569

Answer 3

nice trig, but what does it have to do with a scale drawing?
I think the "pitch" here is a sports field (although quite a small one)
1cm : 2.5m = 5cm : 12.5m

Answer 4

Was visualizing the pitch of a roof.

getting so tired of trying to make sense of poorly worded questions.