1/lambda = R/ni^2–R/nf^2
y = mx + b (standard form) of a linear equation)
x = (y-b)/m
Let,
y = 1/lambda
m = -R
x = 1/nf^2
b = R/ni^2
1/nf^2 = [(1/lamda)-(R/ni^2)]/(-R)
Solve for nf
The Rydberg equation (1/lambda=R/ni^2–R/nf^2) can be treated as a line equation. What is the value of nf as a function of the slope (m) and y-intercept(b)?
5 answers
These are the choices I can choose from:
A. (mb)^1/2
B. –mb^2
C. mb
D. (mb)^1/2
E. (–mb)^1/2
F. None of these are correct.
And when I solve for what you give me, I don't seem to have any of the answers but F. And I wanted to know if that was correct.
A. (mb)^1/2
B. –mb^2
C. mb
D. (mb)^1/2
E. (–mb)^1/2
F. None of these are correct.
And when I solve for what you give me, I don't seem to have any of the answers but F. And I wanted to know if that was correct.
nf would be the square root of some positive value, but your (A) and (B) look the same. Did you copy these alternate answers correctly?
Yeah I copied the answers right.
I don't see how answer A and B are the same.
I don't see how answer A and B are the same.
(–m/b)^1/2 - so is this the answer?