205 = 0.0155 s^2 / 0.3
multiply both sides by 0.3
61.5 = 0.0155 s^2
divide both sides by 0.0155
3968 = s^2
take the square root of both sides
63 miles per hour
the relationship b/w the distance d, in feet, required to stop a vehicle and s, the speed in miles per hour that the vehicle was traveling, is given by the equation
d=0.0155s(squared)/f
f represents the coefficient of friction b/w the tires and the road
*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.
i did 205= 0.0155s(squared)/0.3...idk how to solve this
1 answer