Asked by megan
the relationship b/w the distance d, in feet, required to stop a vehicle and s, the speed in miles per hour that the vehicle was traveling, is given by the equation
d=0.0155s(squared)/f
f represents the coefficient of friction b/w the tires and the road
*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.
i did 205= 0.0155s(squared)/0.3...idk how to solve this
d=0.0155s(squared)/f
f represents the coefficient of friction b/w the tires and the road
*it took a car 205 feet to stop. what speed was the car traveling? use f=0.3 and round your answer to the nearest mile per hour.
i did 205= 0.0155s(squared)/0.3...idk how to solve this
Answers
Answered by
Damon
205 = 0.0155 s^2 / 0.3
multiply both sides by 0.3
61.5 = 0.0155 s^2
divide both sides by 0.0155
3968 = s^2
take the square root of both sides
63 miles per hour
multiply both sides by 0.3
61.5 = 0.0155 s^2
divide both sides by 0.0155
3968 = s^2
take the square root of both sides
63 miles per hour
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.