.........2CH4 ==> C2H2 + 3H2
I ......0.087......0......0
C........-2x.......x......3x
E.....0.087-2x.....x......3x
The problem tells you that 3x = 0.012 which allows you to calculate x and 0.087-2x (as well as 3x). Substitute those values into the Keq expression and evaluate Keq.
The reaction of CH4 in
2CH4(g) ---->/<---- C2H2(g) + 3 H2 (g)
is carried out at a different temperature with an initial concentration of [CH4]=0.087M. At equilibrium, the concentration of H2 is 0.012 M. Find the equilibrium constant at this temperature.
2 answers
0.000608
1 answer