The reaction of 5.7 grams of fluorine with

excess chlorine produced 7.6 grams of ClF3.
What percent yield of ClF3 was obtained?
Answer in units of %.

2 answers

3F2 + Cl2 ==> 2ClF3
mols F2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols F2 to mols ClF3. That will be mols F2 x (2/3) = ?
Then convert mols ClF3 to grams. g = mols x molar mass = ? This is the theoretical yield (TY).

You know from the problem that the actual yield (AY) is 7.6 g.
%yield = (AY/TY)*100 = ?
82.6%
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