The reaction 2NO(g) + 2H2(g) N2(g) + 2H2O(g) goes twice as fast when the concentration of H2 is doubled but four times as fast when the concentration of NO is doubled. What is the overall reaction order?
I did it like this:
k[NO]^m[H2]^n
2r=[H2]^n, meaning that the order for H2 is 1
4r=[NO]^m, meaning that the order for NO is 2
I got overall reaction order to be 3
Did I do this correct, or do I need to use reaction mechanism and ICE tables?
Thanks again!
1 answer
You are absolutely right. Good work.
1 answer