the rays won 33 fewer games than twice as many games as they lost. the total games played was 162. how many wins and how many losses did they have?

Answer 1

ok beginning algebra, eh?
so anyway...

if 162 is the games they played in total
then,
let "x" be the number of games lost
and "2x - 33" be the number games won

so...we know that the total wins plus the total losses must equal total games played...

now we are given this...

x + (2x - 33) = 162

then, solve for "x"

3x = 195

x = 65

so that means the total games lost is 65 games BUT the total games won is given by this....

2x - 33 = (games won)

so just plug in the numbers...

2(65) - 33 = 97

so this means the rays had 97 wins and 65 losses