the rays won 33 fewer games than twice as many games as they lost. the total games played was 162. how many wins and how many losses did they have?

1 answer

ok beginning algebra, eh?
so anyway...

if 162 is the games they played in total
then,
let "x" be the number of games lost
and "2x - 33" be the number games won

so...we know that the total wins plus the total losses must equal total games played...

now we are given this...

x + (2x - 33) = 162

then, solve for "x"

3x = 195

x = 65

so that means the total games lost is 65 games BUT the total games won is given by this....

2x - 33 = (games won)

so just plug in the numbers...

2(65) - 33 = 97

so this means the rays had 97 wins and 65 losses