Let peter have Jim have $4x. Then the given ratio means that Peter has $7x.
Since Jim spent half his money, he now has $2x dollars.
Peter spent $60 and thus now has $(7x-60).
The final ratio of Jim's money to Peter's money is therefore 2x : (7x-60). This is given as 1:2.
Now we just need to solve the proportion by cross-multiplying.
2x : (7x - 60) = 1 : 2
1*(7x - 60) = 2*2x
7x - 60 = 4x
3x = 60
x = 20. Therefore Jim originally had $4x = $80.
The ratio of Jim’s money to Peter’s money was 4 : 7 at first. After
Jim spent half of his money and Peter spent $60, Peter had twice
as much money as Jim. How much money did Jim have at first?
3 answers
Peter & James had the same amount of money. After Peter spend $14.60 and James spend $8.20, James had twice as much money as Peter, how much money had each of them have at first?
To solve this problem, let's assume that both Peter and James initially had x amount of money.
After Peter spent $14.60, he would have x - 14.60 dollars left.
Similarly, after James spent $8.20, he would have x - 8.20 dollars left.
According to the given information, James had twice as much money as Peter after their expenses. Mathematically, we can express this as:
x - 8.20 = 2(x - 14.60)
Now, let's solve this equation to find the value of x:
x - 8.20 = 2x - 29.20
Subtracting x from both sides:
-8.20 = x - 29.20
Adding 29.20 to both sides:
21 = x
Therefore, both Peter and James initially had $21 each.
After Peter spent $14.60, he would have x - 14.60 dollars left.
Similarly, after James spent $8.20, he would have x - 8.20 dollars left.
According to the given information, James had twice as much money as Peter after their expenses. Mathematically, we can express this as:
x - 8.20 = 2(x - 14.60)
Now, let's solve this equation to find the value of x:
x - 8.20 = 2x - 29.20
Subtracting x from both sides:
-8.20 = x - 29.20
Adding 29.20 to both sides:
21 = x
Therefore, both Peter and James initially had $21 each.
1 answer