J/P = 4/7 so J = 4 P/7
P - 3 P/14 = J + 3 P/14
P - 3 P/7 = J = 4 P/7
4 P/7 = 4 P/7
any P OR any J
say J = 8
then P = 14
14 -3 (14/14) = ?? 8 + 3(14/14)
well
11 = 11 sure enough :)
The ratio of Jim's money to Peters money was 4:7 at first. After peter gave 3/14 of his money to jim, they have equal amounts of money. How much money did jim have at first?
2 answers
Let peter have Jim have $4x. Then the given ratio means that Peter has $7x.
Since Jim spent half his money, he now has $2x dollars.
Peter spent $60 and thus now has $(7x-60).
The final ratio of Jim's money to Peter's money is therefore 2x : (7x-60). This is given as 1:2.
Now we just need to solve the proportion by cross-multiplying.
2x : (7x - 60) = 1 : 2
1*(7x - 60) = 2*2x
7x - 60 = 4x
3x = 60
x = 20. Therefore Jim originally had $4x = $80.
Since Jim spent half his money, he now has $2x dollars.
Peter spent $60 and thus now has $(7x-60).
The final ratio of Jim's money to Peter's money is therefore 2x : (7x-60). This is given as 1:2.
Now we just need to solve the proportion by cross-multiplying.
2x : (7x - 60) = 1 : 2
1*(7x - 60) = 2*2x
7x - 60 = 4x
3x = 60
x = 20. Therefore Jim originally had $4x = $80.