The ratio of brown M&M’s in a bag is stated by the candy company to be

Question

56%. If a random sample of 500 bags is selected, determine the probability that
the sample proportion of random bags of M&M’s selected has a percentage of
brown between 51% and 59%
p=.56
standard deviation=sqrt(.56(1-.56)/500)= .0222

Answer 1

Since you have the mean and sd
plug in your range into

http://davidmlane.com/hyperstat/z_table.html

(one of the best sites for replacing all those nasty tables in the back of your text)