dp/dt = 3t^2 + 6t
p(t) = t^3 + 3t^2 + C
Now use p(1) = 100 to find C.
the rate of the growth of population of bacteria is modelled by the equation dp/dt = 3t^2 + 6t where p is the population size at time t hours given that p = 100 when t = 1, find p in terms of t
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