The population, p in thousands of bacteria colony can be modelled by the function p(t)=200+20t-t^2, where t is the time, in hours, t is greater than or equal to zero.
a) Determine the growth rate of the bacteria population at each of the following times.
i>3h
ii>8h
Ans: find the 1st derivative which is 20-2t, substitute the times given and it yield a negative number and that in thousands is the answer.
b)What are the implications of the growth rates in part a)
Ans: since the answer are negative they suggest that the population of the bacteria is decreasing.
c)When does the bacteria population stop growing? What is the population at this time.
Ans: set the original equation to zero it will give a time in hours and substitute that time into the first derivative.
2 answers
It seems to me that your question contains the answers, or at least the means of calculating them. Why just you don't just follow those directions?
i just wanted to know if it is the correct way of going about with them, i forgot to put the (check) in the title.
2 answers