If P'(x)=xe^(-x^2) , then
P(x) = (-1/2) e^(-x^2) + c
when t= 3 , P(3) = 10000
10000= (-1/2)e^(-9) + c
10000 = -.00006 + c
c = 10000.0000617
1. P(x) = (-1/2) e^(-x^2) + 10000.0000617
2. "in the long run" implies x --->∞
which means (-1/2) e^(-x^2) ---> 0
so P(∞) = 10000.0000617
The rate of growth of the profit is approximated by P'(x)=xe^(-x^2) where x represents time measured in years. The total profit in the third year that the new technology is in operation is $10,000.
1.Find the total profit function
2. what happens to the total amount of profit in the long run?
1 answer
1 answer