Asked by Ana
The rate constant for a second order reaction has the value of 2.5 x 10–3 L·mol–1·s–1. If the initial concentration of reactant is 3.5 mol·L-1, what will be the molar concentration of the reactant after 2.5 minutes?
Answers
Answered by
DrBob222
[1/(A)] - [1/(Ao)] = kt
k is given in seconds; therefore, change 2.5 minutes to seconds.
k is given in seconds; therefore, change 2.5 minutes to seconds.
Answered by
Ana
I did that and but I got 1.52 mol/L rather 0.97 (as the answer key provides it)
Answered by
DrBob222
I obtained 1.51 which is essentially the same as your answer. Did they give a reaction? The formula actually is
1/A - 1/Ao = akt so the a could change things but usually is not a number like 2/3. Must be a wrong answer. If you find to the contrary please be sure and post so I will know. However, I don't see anything wrong with what we've done.
1/A - 1/Ao = akt so the a could change things but usually is not a number like 2/3. Must be a wrong answer. If you find to the contrary please be sure and post so I will know. However, I don't see anything wrong with what we've done.
Answered by
Ana
No, they did not provide any reaction for this problem. If I'll find the solution, I'll post it here. Thank you for your help.
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