Question
At a given temperature, the elementary reaction A <=> B in the forward direction is first order in A with a rate constant of 2.60 x 10^-2 s^-1. The reverse reaction is first order in B and the rate constant is 8.50 x 10^-2 s^-1.
What is the value of the equilibrium constant for the reaction A <=> B at this temperature and
What is the value of the equilibrium constant for the reaction B <=> A at this temperature?
do you I take 2.60 x 10^-2 s^-1/8.50 x 10^-2 s^-1 for the first and 8.50 x 10^-2 s^-1/2.60 x 10^-2 s^-1 for the second..?
What is the value of the equilibrium constant for the reaction A <=> B at this temperature and
What is the value of the equilibrium constant for the reaction B <=> A at this temperature?
do you I take 2.60 x 10^-2 s^-1/8.50 x 10^-2 s^-1 for the first and 8.50 x 10^-2 s^-1/2.60 x 10^-2 s^-1 for the second..?
Answers
That's what I would do.
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