The range of a target is found to be 20km.A shell leaves again with a velocity of 500ms-1.what must be the angle of elevation of the gun.if the ground is leveled.

Answer 1

20km=timeinair*500*cosAngle
solve for time in air.
in the vertical
hf=hi+vi*timeinair-1/2 *(9.8)timeinair^2
or time in air=500*sinAngle/4.9
solve now for the angle.

Answer 2

Range = Vo^2*sin(2A)/g = 20,000 m.
500^2*sin(2A)/9.8 = 20.000,
2A =
A =