Kepler's third law:
The ratio of the squares of the periods of any two planets is equal to the ratio of the cubes of their average distances from the sun. (The Law of Harmonies)
(periodsecond/24hrs)^2= (36000/9000)^3
period second= 24 sqrt (36/9)^3
The radius of the orbit of a geosynchronous satellite is 36000 km. then the period of revolution of a satellite with its
orbital radius 9000 km would be ?
2 answers
the period of revolution is 3 hrs
1 answer