k = 0.693/half life = ?
Then ln(No/N) = kt
You know k.
No = initial amount. It is given but it may be in your problem and you didn't include that in your post. If so put that in. If not, you can't answer in amounts except in %. In that case place a 100 for No.
N = amount left
t = 60 days. After you find N,
Then N/No will be the fraction left.
The radioactive isotope, phosphorus-32, has a half-life of 14.26 days. How much phosphorus-32 will remain after 60 days? Please help.
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