k = 0.693/t1/2
Substitute k into the below equation.
ln(No/N) = kt
No = The problem doesn't say how much to start with so start with 100 grams.
N = what you end up with after 60 days.
k from above.
t = 60 days
Starting with 100 g will give you a fraction and that x 100 will give you a percentage of the amount you start with that will remain after 60 days.
The radioactive isotope, phosphorus-32, has a half-life of 14.26 days. How much phosphorus-32 will remain after 60 days?
Please help.
2 answers
3.743
1 answer