Assuming the fluid is H2O and not ethylene glycol, then
q in joules = mass H2O x specific heat H2O x (Tfinal-Tinitial)
and I would substitute 17,000 g for mass H2O
The radiator in your car uses either water or ethylene glycol (anti-freeze) to remove heat from the engine and dissipate it to the outside air. If the water recirculation rate is 17.0 kg per minute of water and the water temperature leaving the engine and entering the radiator is 86.0 C and the temperature of the water leaving the radiator and entering the engine is 46.0 C, then how much energy (kJ) is dissipated by the radiator per minute? The specific heat capacity of water is 4.18 J/g ·K. The units are kJ/minute. The error interval is +/- 5%.
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so i did 17000 x4.18x(86-46)=284 is that what you meant
Yes, it's what I meant but 284 isn't the right answer if that is 284 J/min. Punch those numbers into the calculator again and remember the answer should be in kJ.
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