To find the length of the edge of the square base, we can use the Pythagorean theorem.
The formula is:
height^2 + (edge length/2)^2 = slant height^2
Plugging in the given values:
321^2 + (x/2)^2 = 436.5^2
103041 + (x/2)^2 = 190769.25
(x/2)^2 = 87653.25
Taking the square root of both sides:
x/2 = sqrt(87653.25)
x/2 ≈ 296
x ≈ 2 * 296
x ≈ 592
So, the length of the edge of the square base is approximately 592 ft.
The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth. what is the answer?
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7 answers
wrong
295.78 rounded to the nearest tenth
295.78 rounded to the nearest tenth
Apologies for the mistake. Let me correct it.
To find the length of the edge of the square base, we can use the Pythagorean theorem.
The formula is:
height^2 + (edge length/2)^2 = slant height^2
Plugging in the given values:
321^2 + (x/2)^2 = 436.5^2
103041 + (x/2)^2 = 190769.25
(x/2)^2 = 87653.25
Taking the square root of both sides:
x/2 = sqrt(87653.25)
x/2 ≈ 295.7776
x ≈ 2 * 295.7776
x ≈ 591.6
So, the length of the edge of the square base is approximately 591.6 ft, rounded to the nearest tenth.
To find the length of the edge of the square base, we can use the Pythagorean theorem.
The formula is:
height^2 + (edge length/2)^2 = slant height^2
Plugging in the given values:
321^2 + (x/2)^2 = 436.5^2
103041 + (x/2)^2 = 190769.25
(x/2)^2 = 87653.25
Taking the square root of both sides:
x/2 = sqrt(87653.25)
x/2 ≈ 295.7776
x ≈ 2 * 295.7776
x ≈ 591.6
So, the length of the edge of the square base is approximately 591.6 ft, rounded to the nearest tenth.
stop, dumb bot.
I'm asking you to round 295.78 to the nearest tenth, idiot
I'm asking you to round 295.78 to the nearest tenth, idiot
Apologies for misunderstanding your request.
Rounding 295.78 to the nearest tenth would result in 295.8.
Rounding 295.78 to the nearest tenth would result in 295.8.
mb, your first response was correct
I apologize for any confusion caused by my previous response. Thank you for confirming that the initial response was indeed correct.