To find the length of the edge of the square base, we can use the Pythagorean theorem.
Let's call the length of the edge of the square base x. According to the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
Simplifying the equation, we get:
x^2 + 103041 ft.^2 = 190523.25 ft.^2
Subtracting 103041 ft.^2 from both sides, we get:
x^2 = 87482.25 ft.^2
Taking the square root of both sides, we get:
x ≈ √87482.25 ft.^2 ≈ 295.7 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.7 ft. Rounded to the nearest tenth, the length is 295.7 ft.
The Pyramid is an arena in Memphis, Tennessee. Its height is 321 ft., and its slant height is 436.5 ft. Find the length of the edge of the square base. Round the answer to the nearest tenth.
17 answers
thats incorrect
Apologies for the mistake. Let's recalculate it correctly:
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190512.25 ft.^2
x^2 = 190512.25 ft.^2 - 103041 ft.^2
x^2 = 87471.25 ft.^2
Taking the square root of both sides, we get:
x = √87471.25 ft.^2 ≈ 295.7 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.7 ft. (rounded to the nearest tenth).
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190512.25 ft.^2
x^2 = 190512.25 ft.^2 - 103041 ft.^2
x^2 = 87471.25 ft.^2
Taking the square root of both sides, we get:
x = √87471.25 ft.^2 ≈ 295.7 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.7 ft. (rounded to the nearest tenth).
its still incorrect
Apologies for the confusion. Let's calculate it correctly:
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190522.25 ft.^2
x^2 = 87481.25 ft.^2
Taking the square root of both sides, we get:
x ≈ √87481.25 ft.^2 ≈ 295.6 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.6 ft. (rounded to the nearest tenth).
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190522.25 ft.^2
x^2 = 87481.25 ft.^2
Taking the square root of both sides, we get:
x ≈ √87481.25 ft.^2 ≈ 295.6 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.6 ft. (rounded to the nearest tenth).
its wrong
Apologies for the incorrect calculation. Let's try again:
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190512.25 ft.^2
x^2 = 87471.25 ft.^2
Taking the square root of both sides, we get:
x ≈ √87471.25 ft.^2 ≈ 295.5 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.5 ft. (rounded to the nearest tenth).
Using the Pythagorean theorem, we have:
x^2 + (321 ft.)^2 = (436.5 ft.)^2
x^2 + 103041 ft.^2 = 190512.25 ft.^2
x^2 = 87471.25 ft.^2
Taking the square root of both sides, we get:
x ≈ √87471.25 ft.^2 ≈ 295.5 ft.
Therefore, the length of the edge of the square base of the Pyramid is approximately 295.5 ft. (rounded to the nearest tenth).
For the square pyramid, the lateral edge length, e , is 25 in., and the slant height, s , is 24 in. Find the height of the pyramid, h . Round the answer to the nearest whole number. Hint: Before finding the length of h , you will first need to find the length of r
.
(1 point)
The height of the square pyramid is
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(1 point)
The height of the square pyramid is
To find the height of the square pyramid, we need to find the length of the vertical height of the pyramid.
We can use the Pythagorean theorem to relate the height, slant height, and the length of the lateral edge.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Let's call the height of the pyramid "h" and the length of the slant height "s". The length of the lateral edge is given as "e".
Using the Pythagorean theorem, we have:
h^2 + r^2 = s^2
Since the lateral edge length is given as 25 inches, and it connects the midpoint of the base to the vertex, we know that the lateral edge divides the base into two congruent right triangles. Half of the base, which is a side of the right triangle, is equal to r/2.
So, we can rewrite the equation as:
h^2 + (r/2)^2 = s^2
Substituting the given values, we have:
h^2 + (25/2)^2 = 24^2
Simplifying the equation, we get:
h^2 + 625/4 = 576
Multiplying both sides by 4 to remove the fraction, we have:
4h^2 + 625 = 2304
Subtracting 625 from both sides, we get:
4h^2 = 1679
Dividing both sides by 4, we have:
h^2 = 419.75
Taking the square root of both sides, we get:
h = √419.75
Calculating the square root of 419.75, we get:
h ≈ 20.5
Therefore, the height of the square pyramid is approximately 20.5 inches when rounded to the nearest whole number.
We can use the Pythagorean theorem to relate the height, slant height, and the length of the lateral edge.
The Pythagorean theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides.
Let's call the height of the pyramid "h" and the length of the slant height "s". The length of the lateral edge is given as "e".
Using the Pythagorean theorem, we have:
h^2 + r^2 = s^2
Since the lateral edge length is given as 25 inches, and it connects the midpoint of the base to the vertex, we know that the lateral edge divides the base into two congruent right triangles. Half of the base, which is a side of the right triangle, is equal to r/2.
So, we can rewrite the equation as:
h^2 + (r/2)^2 = s^2
Substituting the given values, we have:
h^2 + (25/2)^2 = 24^2
Simplifying the equation, we get:
h^2 + 625/4 = 576
Multiplying both sides by 4 to remove the fraction, we have:
4h^2 + 625 = 2304
Subtracting 625 from both sides, we get:
4h^2 = 1679
Dividing both sides by 4, we have:
h^2 = 419.75
Taking the square root of both sides, we get:
h = √419.75
Calculating the square root of 419.75, we get:
h ≈ 20.5
Therefore, the height of the square pyramid is approximately 20.5 inches when rounded to the nearest whole number.
Given l=30 in. , w=20 in. , h=18 in. , and x=36.1 in. , find the length of d . Round the answer to the nearest tenth.
(1 point)
(1 point)
To find the length of d, we need to use the Pythagorean theorem.
d is the hypotenuse of a right triangle formed by l, w, and d.
Using the Pythagorean theorem, we have:
d^2 = l^2 + w^2
Substituting the given values, we have:
d^2 = 30^2 + 20^2
d^2 = 900 + 400
d^2 = 1300
Taking the square root of both sides, we have:
d ≈ √1300
Calculating the square root of 1300, we get:
d ≈ 36.06
Therefore, the length of d is approximately 36.1 inches when rounded to the nearest tenth.
d is the hypotenuse of a right triangle formed by l, w, and d.
Using the Pythagorean theorem, we have:
d^2 = l^2 + w^2
Substituting the given values, we have:
d^2 = 30^2 + 20^2
d^2 = 900 + 400
d^2 = 1300
Taking the square root of both sides, we have:
d ≈ √1300
Calculating the square root of 1300, we get:
d ≈ 36.06
Therefore, the length of d is approximately 36.1 inches when rounded to the nearest tenth.
thats wrong
Apologies for the mistake. Let's recalculate it correctly:
Using the Pythagorean theorem, we have:
d^2 = l^2 + w^2
Substituting the given values, we have:
d^2 = 30^2 + 20^2
d^2 = 900 + 400
d^2 = 1300
Taking the square root of both sides, we have:
d ≈ √1300
Calculating the square root of 1300, we get:
d ≈ 36.06
Therefore, the length of d is approximately 36.1 inches when rounded to the nearest tenth.
Using the Pythagorean theorem, we have:
d^2 = l^2 + w^2
Substituting the given values, we have:
d^2 = 30^2 + 20^2
d^2 = 900 + 400
d^2 = 1300
Taking the square root of both sides, we have:
d ≈ √1300
Calculating the square root of 1300, we get:
d ≈ 36.06
Therefore, the length of d is approximately 36.1 inches when rounded to the nearest tenth.
what is 36.1 in rounded to the nearest tenth
36.1 inches rounded to the nearest tenth would be 36.1 inches itself, since it is already rounded to the nearest tenth.
295.8
591.6
15 answers