The product of two consecutive integers, n and n+1, is 42. What is the positive integer that satisfies the situation? Is it 6 x 7?
3 answers
Your answer is correct. How did you get it?
That two consecutive numbers that multiply and equal 42 is 6x7. 6 + 1+7
But, did you solve it using algebra?
n(n + 1) = 42
n^2 + n - 42 = 0
( n-6)(n+7) = 0
n = 6 or n = -7
n cannot = -7
therefore n = 6 and n + 1 = 7
n(n + 1) = 42
n^2 + n - 42 = 0
( n-6)(n+7) = 0
n = 6 or n = -7
n cannot = -7
therefore n = 6 and n + 1 = 7