Since there is no value of x that will
make the denominator = 0, the Domain
is all real values oF X.
The problem is to find the domain of 2x+7 / x^3-5x^2-9x+18. I know that x^3-5x^2-9x+18 cannot = 0. What I can't remember is how to solve x^3-5x^2-9x+18 ≠ 0. Thanks!
2 answers
X(x^2+1)(x-3)/x-2=0