normal force: weight of the cart+downward component of pushing.
fn=mg+F*sin30
friction= mu*fn
you did not state the pushing force value.
No work is done by the normal force, because the cart does not go in that direction.
The problem goes like this...
You are pushing a shopping cart at a constant speed. The handle makes an angle of 30.0 degrees with the horizontal and the friction in the cart has a coefficient of 0.400 to account for all the axles, etc. The mass of the cart is 45.0-kg and we are pushing it a distance of 35.0 meters along a level floor. Find the "normal" force and the work due to that force.
I know that the answers are 573 N and 0 J respectively but I don't know how to get these answers. Please help!
4 answers
Thanks, I got that far but the question was asked exactly as I wrote it. My teacher did not include a pushing force value. Can you think of any way to find the normal force without it?
Sure: Go to the market and get a crystal ball that can see inside your teacher's mind. The question is flawed.
Alright, but thanks anyway!
1 answer