To determine the correct answer, we can apply Newton's second law of motion, which states that force equals mass times acceleration (F = m * a). If both people are using the same amount of force to push their respective shopping carts, we can analyze how the different masses will affect their acceleration (and therefore their change in motion).
Let’s denote the force applied by both individuals as \( F \).
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For the first shopping cart (with mass \( m_1 \)): \[ F = m_1 \cdot a_1 \] Thus, we can express acceleration as: \[ a_1 = \frac{F}{m_1} \]
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For the second shopping cart (with mass \( m_2 \)), where \( m_2 < m_1 \): \[ F = m_2 \cdot a_2 \] Thus, we can express acceleration as: \[ a_2 = \frac{F}{m_2} \]
Since \( m_2 < m_1 \), this implies: \[ a_2 = \frac{F}{m_2} > a_1 = \frac{F}{m_1} \] This means the second shopping cart (the lighter one) will have a greater acceleration compared to the first shopping cart (the heavier one) under the same applied force.
Considering "change in motion" as related to acceleration, we find:
- The second shopping cart (with less mass) will experience a greater change in motion than the first shopping cart (with more mass).
Therefore, the correct answer is:
C. The second shopping cart has a greater change in motion than the first shopping cart.
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