prob(Joe not at work) = .51
prob(Joe not at home) = .75
prob(joe not at work and not at home)
= (.51)(.75) = .3825
= 38%
Don't know how they got 39%
The probability Joe is at work is 49%,. The probability Joe is at home is 25%. What is the probability Joe is neither at work nor at home?
a) 39%
b)74%
c)52%
d) 26%
*I personally think it is a or c. I am just needing some help thanks!
1 answer