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The pressure on an object P is proportional to the temperature and inversely proportional to the volume: π=ππ
P
=
T
V
with P measured in Pascals. In this case the temperature and the volume both depend on time, hence so the does the pressure: π(π‘)=π(π‘)π(π‘)
P
(
t
)
=
T
(
t
)
V
(
t
)
. At time π‘=8
t
=
8
seconds the temperature of an object is 85πΆ
85
C
and increasing at a rate of β5πΆπ
β
5
C
s
and the volume is 20π3
20
m
3
and increasing at the rate β8π2π
β
8
m
2
s
.
Using the quotient rule, the pressure on the object is changing at the rate
1 answer