E=sigma/epsilion
Force=Eq=sigma/epsilion * e
and
F=ma or a= F/masselectron
time t in field= distance/Velociyt
t=.0105m/1.11E6 second
distancedeviated:
d=1/2 a t^2
so compute
The positive and negative plates of a parallel-plate capacitor have an area of 1.05 cm by 1.05 cm. Their surface charge densities are +1.00×10-6 C/m2 and -1.00×10-6 C/m2, respectively. A proton moving parallel to the plates enters the middle of the space between them at a speed of 1.15×106 m/s. Assuming the field outside the capacitor is 0 and the field inside is uniform, how far to the side will the proton's path have deviated when it gets to the far end of the capacitor?
2 answers
Force=Eq=sigma/epsilion * e
what does the lower case 'e' stand for, in the above equation?
what does the lower case 'e' stand for, in the above equation?
1 answer