Oh all right I will do one more before getting grandkids up for school.
dr/dt = (3.2+3.6t)i + (1.7-4.8t)j
d^2r/dt^2 = 3.6 i - 4.8 j
which is the acceleration, so what else is new?
|a| = sqrt(3.6^2 + 4.8^2)
tan angle north of east = -4.8/3.6
so angle South of East = 53.1 deg
The position of an object as a function of time is r⃗ =(3.2t+ 1.8 t2)i^+(1.7t− 2.4 t2)j^m, where t is the time in seconds.
Find the object’s magnitude of the acceleration.
What is the direction of the acceleration?
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