e^0 = 1
so initial is
2530e^(0) = 2530
The population of bacteria present after t hours is given by the function P(t) = 2530e^(0.24t)
.
(a) What is the initial population of the bacteria?
(b) How long will it take the population to reach 10,000?
2 answers
2530e^(0.24t) = 10,000
e^.24 t = 3.953
ln [e^.24 t ]= ln 3.953
.24 t = 1.374
e^.24 t = 3.953
ln [e^.24 t ]= ln 3.953
.24 t = 1.374
1 answer