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The population of a city with 15,000 people declines at a rate of 2% each year. Which is an exponential equation that models th...Question
The population of a city with 15,000 people declines at a rate of 2% each year.
Which is an exponential equation that models the population, y, after x years?
(1 point)
Responses
y=15,000⋅(2)x
𝑦
=
15
,
000
⋅
(
2
)
𝑥
y is equal to 15 comma 000 times 2 to the x th power
y=15,000⋅(0.98)x
𝑦
=
15
,
000
⋅
(
0.98
)
𝑥
y is equal to 15 comma 000 times 0 point 9 8 to the x th power
y=15,000⋅(98)x
𝑦
=
15
,
000
⋅
(
98
)
𝑥
y is equal to 15 comma 000 times 98 to the x th power
y = 15,000 ⋅ 0.98x
Which is an exponential equation that models the population, y, after x years?
(1 point)
Responses
y=15,000⋅(2)x
𝑦
=
15
,
000
⋅
(
2
)
𝑥
y is equal to 15 comma 000 times 2 to the x th power
y=15,000⋅(0.98)x
𝑦
=
15
,
000
⋅
(
0.98
)
𝑥
y is equal to 15 comma 000 times 0 point 9 8 to the x th power
y=15,000⋅(98)x
𝑦
=
15
,
000
⋅
(
98
)
𝑥
y is equal to 15 comma 000 times 98 to the x th power
y = 15,000 ⋅ 0.98x
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To model the population decline of a city with a declining rate of 2% per year, we can start with the initial population and apply the rate of decline.
The population after x years can be modeled by the equation:
\[
y = P \cdot (1 - r)^x
\]
where:
- \( P \) is the initial population (15,000 in this case),
- \( r \) is the rate of decline (2% or 0.02),
- \( (1 - r) \) is the remaining population after decline (which is \( 1 - 0.02 = 0.98 \)).
Substituting the values, we get:
\[
y = 15,000 \cdot (0.98)^x
\]
Thus, the correct equation that models the population \( y \) after \( x \) years is:
\[
y = 15,000 \cdot (0.98)^x
\]
This corresponds to the option:
**y = 15,000 ⋅ (0.98)^x**
The population after x years can be modeled by the equation:
\[
y = P \cdot (1 - r)^x
\]
where:
- \( P \) is the initial population (15,000 in this case),
- \( r \) is the rate of decline (2% or 0.02),
- \( (1 - r) \) is the remaining population after decline (which is \( 1 - 0.02 = 0.98 \)).
Substituting the values, we get:
\[
y = 15,000 \cdot (0.98)^x
\]
Thus, the correct equation that models the population \( y \) after \( x \) years is:
\[
y = 15,000 \cdot (0.98)^x
\]
This corresponds to the option:
**y = 15,000 ⋅ (0.98)^x**
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