Asked by Anonymous
the population of a city can be modeled using the equation p=40,000x(9/10)^x. one year the population was 23620. what was the following population a year later.
Answers
Answered by
Reiny
So let's solve
40,000x(9/10)^x = 23620
I will assume that the x after 40,000 is supposed to be a multiplication sign and not a variable,
If it is a variable you have an completely ridiculously hard equation to solve,
If we take it as
40,000(9/10)^x = 23620
then x = 5 is a solution, (too nice not be be that way)
so we want the population when x = 6
P = 40000((9/10)^6
= 21258
40,000x(9/10)^x = 23620
I will assume that the x after 40,000 is supposed to be a multiplication sign and not a variable,
If it is a variable you have an completely ridiculously hard equation to solve,
If we take it as
40,000(9/10)^x = 23620
then x = 5 is a solution, (too nice not be be that way)
so we want the population when x = 6
P = 40000((9/10)^6
= 21258
Answered by
Anonymous
o i get it thank you
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