The points A(1,5) and B(9,3) are part of a triangle ΔABC. The triangle has a right angle at A and and sides satisfy AB=2AC. Find a point C such that C lies above the line AB.

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what is length AB?
sqrt(4+ 64) = sqrt 68 = 2 sqrt 17
so
length AC = sqrt 17

what is slope AC?
It is -1/slope AB
slope AB = -2/8 = -1/4
so
slope AC = 4
now point C (x,y)
Oh, wow, problem over
go right one from A
go up 4 from there
what is hypotenuse?
LOL sqrt 17 !!!!
so
x = 1 + 1 = 2
y = 5 + 4 = 9
C(2,9)
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