The point P (−1,2)
is rotated to become P′ (2,1). Describe the rotation by degree and direction.
90°
−90°
180°
−270°
7 answers
The rotation is 90° counter-clockwise.
The point Q(−5,−9)
is rotated −270°
about the origin. Select the location of Q′.
is rotated −270°
about the origin. Select the location of Q′.
The point Q' is located at (-9, 5).
A quadrilateral with vertices G(−10,1)
, E(−6,−4)
, O(2,0)
, and M(0,4)
is rotated about the origin 270 degrees (counterclockwise). Apply rotation mapping rules to find the image of M
.
, E(−6,−4)
, O(2,0)
, and M(0,4)
is rotated about the origin 270 degrees (counterclockwise). Apply rotation mapping rules to find the image of M
.
To rotate a point (x, y) counterclockwise about the origin by 270 degrees, we can apply the following rotation mapping rules:
x' = x * cos(270°) - y * sin(270°)
y' = x * sin(270°) + y * cos(270°)
Plugging in the coordinates of point M (0, 4), we get:
x' = 0 * cos(270°) - 4 * sin(270°) = 0 + 4 * (-1) = -4
y' = 0 * sin(270°) + 4 * cos(270°) = 0 + 4 * (0) = 0
Therefore, the image of M after rotating the quadrilateral about the origin by 270 degrees is M' (-4, 0).
x' = x * cos(270°) - y * sin(270°)
y' = x * sin(270°) + y * cos(270°)
Plugging in the coordinates of point M (0, 4), we get:
x' = 0 * cos(270°) - 4 * sin(270°) = 0 + 4 * (-1) = -4
y' = 0 * sin(270°) + 4 * cos(270°) = 0 + 4 * (0) = 0
Therefore, the image of M after rotating the quadrilateral about the origin by 270 degrees is M' (-4, 0).
A figure is rotated 90 degrees counterclockwise about the origin. Which of the following function mappings was applied? Enter the number of the correct option.
Option #1: (x,y)→(y,−x)
Option #2: (x,y)→(−y,x)
Option #3: (x,y)→(−x,−y)
Option #4: (x,y)→(y,x)
Option #1: (x,y)→(y,−x)
Option #2: (x,y)→(−y,x)
Option #3: (x,y)→(−x,−y)
Option #4: (x,y)→(y,x)
The correct option is Option #2: (x,y)→(−y,x).
1 answer