Asked by Nowhen
                The point Q(−5,−9) is rotated −270° about the origin. Select the location of Q′ .
A. Q'(9,5)
B. Q' (-5,9)
C. Q' (5,9)
D. Q' (9,-5)
            
            
        A. Q'(9,5)
B. Q' (-5,9)
C. Q' (5,9)
D. Q' (9,-5)
Answers
                    Answered by
            Nowhen
            
    Are you sure you are correct.
    
                    Answered by
            GPT-4o mini
            
    To find the new coordinates of point Q(-5, -9) after a rotation of -270° about the origin, we can first convert the angle to a positive angle. 
-270° is equivalent to +90° since rotating clockwise is negative and counter-clockwise is positive.
To rotate a point (x, y) by 90° counter-clockwise about the origin, the new coordinates (x', y') are given by:
- \( x' = -y \)
- \( y' = x \)
Now, applying these transformations to the point Q(-5, -9):
1. \( x' = -(-9) = 9 \)
2. \( y' = -5 \)
Thus, the new coordinates after rotating Q(-5, -9) -270° (or +90°) about the origin are Q'(9, -5).
Therefore, the correct answer is:
**D. Q' (9, -5)**
    
-270° is equivalent to +90° since rotating clockwise is negative and counter-clockwise is positive.
To rotate a point (x, y) by 90° counter-clockwise about the origin, the new coordinates (x', y') are given by:
- \( x' = -y \)
- \( y' = x \)
Now, applying these transformations to the point Q(-5, -9):
1. \( x' = -(-9) = 9 \)
2. \( y' = -5 \)
Thus, the new coordinates after rotating Q(-5, -9) -270° (or +90°) about the origin are Q'(9, -5).
Therefore, the correct answer is:
**D. Q' (9, -5)**
                    Answered by
            GPT-4o mini
            
    Let's go through the rotation of point \( Q(-5, -9) \) about the origin by an angle of \(-270^\circ\) step by step to ensure accuracy:
1. **Understanding the rotation**:
- A rotation of \(-270^\circ\) is equivalent to rotating by \(90^\circ\) counterclockwise, since \(-270 + 360 = 90\).
2. **Rotation transformation**:
- The rules for rotating a point \((x, y)\) by \(90^\circ\) counterclockwise around the origin are:
- \( x' = -y \)
- \( y' = x \)
3. **Substituting in the original point**:
- For point \( Q(-5, -9) \):
- \( x = -5 \)
- \( y = -9 \)
4. **Calculating the new coordinates**:
- \( x' = -y = -(-9) = 9 \)
- \( y' = x = -5 \)
So, the coordinates of \( Q' \) after the rotation are:
- \( Q'(9, -5) \)
Therefore, the correct answer is:
**D. \( Q'(9, -5) \)**
Thank you for your patience, and I confirm that my previous response was accurate.
    
1. **Understanding the rotation**:
- A rotation of \(-270^\circ\) is equivalent to rotating by \(90^\circ\) counterclockwise, since \(-270 + 360 = 90\).
2. **Rotation transformation**:
- The rules for rotating a point \((x, y)\) by \(90^\circ\) counterclockwise around the origin are:
- \( x' = -y \)
- \( y' = x \)
3. **Substituting in the original point**:
- For point \( Q(-5, -9) \):
- \( x = -5 \)
- \( y = -9 \)
4. **Calculating the new coordinates**:
- \( x' = -y = -(-9) = 9 \)
- \( y' = x = -5 \)
So, the coordinates of \( Q' \) after the rotation are:
- \( Q'(9, -5) \)
Therefore, the correct answer is:
**D. \( Q'(9, -5) \)**
Thank you for your patience, and I confirm that my previous response was accurate.
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