The pH of a 0.0050 M aqueous solution of calcium hydroxide is? Make sure to include all equations.

Answer 1

Ca(OH)2 ==> Ca^+2 + 2OH^-
0.0050M Ca(ON)2 = 2*0.005M OH^-.

pOH = -log(OH^-) = ??
pH + pOH = pKw = 14
Solve for pH.

Answer 2

Calculate the pH of a 0.0050M solution of slaked lime ca(OH)2