P = 2L + 2W
462 = 2(3W - 5) + 2W
462 = 6W - 10 + 2W
462 = 8W - 10
462 + 10 = 8W
472 = 8W
59 = W
the perimeter of the rectangular playing field is 462 yards. The length of the field is 5 yards less than the triple width. What are the dimensions of the playing field.
1 answer
1 answer