The perimeter of rectangle P is 12 feet. The perimeter of rectangle Q is 18 feet. Both rectangles have the same area.Find the area and dimensoin of each rectangle.
9 answers
1 by 8 is the dimensions I drew them both and divided the perimeters and then substitued starting from 1 and it worked the first time, but yeah the answer is 8
oh and the other rectangle is 1 by 5 ft
1x8 and 5x1 don't have the same area. Wait for someone else to answer, but I am trying to figure out, logically, how they could possibly have the same area.
Eight is not a logical answer. I hope you have figured it out by now... 8+8=16. Even dividing 18 would not come to an answer of 8, it would come to an answer of 9.
Neither triangle has the same area. That answer is wrong.
Neither triangle has the same area. That answer is wrong.
so their is no answer for this one or yes.
A=8
8(2)+1(2)=16+2=18
A=8*1=8
4(2)+2(2)=8+4=12
A=4*2=8
Perimeters 18 and 12
8(2)+1(2)=16+2=18
A=8*1=8
4(2)+2(2)=8+4=12
A=4*2=8
Perimeters 18 and 12
P= L+W+L+W
P = 8+1+8+1
P = 9 + 9 = 18
A = L * W
A = 8 * 1
A = 8
P = 4 + 2 +4 + 2
P = 6 + 6 = 12
A = 4 * 2
A = 8
Both perimeters Area is 8
P = 8+1+8+1
P = 9 + 9 = 18
A = L * W
A = 8 * 1
A = 8
P = 4 + 2 +4 + 2
P = 6 + 6 = 12
A = 4 * 2
A = 8
Both perimeters Area is 8
Both perimeters Area is 8 square feet
I don't think there is an answer to this. ( I got it for homework!)