the perimeter of a rectangle is twice the sum of its width and it length. the perimeter is 40meters and its lenght is 2 meters more than twice its width.

Answer 1

L = 2W + 2

2L + 2W = 40

Substitute 2W+2 for L in second equation and solve for L. Insert that value into the first equation and solve for W. Check by inserting both values into the second equation.

Answer 2

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