The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Find the maximum width of the rectangle.
3 answers
you have 2 lengths of 125, so you use up 250. Now you have 50 left, the 2 other sides must be even in order to be a rectangle. So divide 50 by 2 and you get 25. Therefore the rectangles sides are 125,125, 25,2.
But maybe use algebra. I do not know what math carly is taking.
2 L + 2 W </= 300
250 + 2 W </= 300
2 W </= 50
W </= 25
2 L + 2 W </= 300
250 + 2 W </= 300
2 W </= 50
W </= 25
56>[=2