the perimeter of a rectangle is 70m. if the width were doubled and length were increased by 24m, the perimeter would be 142m. what are the length and width of the rectangle?

Answer 1

W+W+L+L=70
(2W)+(2W)+(L+24)+(L+24)=142

Solve for W in terms of L.
W+W+L+L=70
W=(70-2L)/2
Use substitution to find L.
(2[(70-2L)/2])+(2[(70-2L)/2])+(L+24)+(L+24)=142
Then Plug the L value back into W=(70-2L)/2 to find W