P = 2L + 2W
226 = 2W + 2(W + 37)
226 = 4W + 74
226 - 74 = 4W
152 = 4W
38 = W
Take it from there.
the perimeter of a rectangle is 226 inches. the length exceeds the width by 37 inches. find the length and the width.
1 answer
1 answer