the perimeter of a rectangle is 112 inches. The length exceeds the width by 50 inches and width.

Answer 1

please someone help it is due tonight I have tried all I know how to figure it out

Answer 2

Let w=width
Length=w+50
Permeter=2(length+width)
=2(w+50+w)

Solve for w in
2(w+50+w)=112