Asked by Patricia
The only two forces acting on a body have magnitudes F1 and F2 and directions that differ by an angle θ. If the resulting acceleration has a magnitude a, what is the mass of the body?
Answers
Answered by
Damon
Fx = F1 + F2 cos T
Fy = F2 sin T
F = sqrt (Fx^2+Fy^2)
Fx^2 = F1^2 + 2 F1F2 cos T + F2^2 cos^2 T
Fy^2 = F2^2 sin^2 T
sum = F1^2 + 2 F1F2 cos T + F2^2(sin^2T+cos^2T)
sum = F1^2 + 2 F1 F2 cos T + F2^2
so
F = sqrt (F1^2 + 2 F1 F2 cos T + F2^2)
and
m = F/a
=(1/a)sqrt(F1^2 + 2 F1 F2 cos T + F2^2)
Fy = F2 sin T
F = sqrt (Fx^2+Fy^2)
Fx^2 = F1^2 + 2 F1F2 cos T + F2^2 cos^2 T
Fy^2 = F2^2 sin^2 T
sum = F1^2 + 2 F1F2 cos T + F2^2(sin^2T+cos^2T)
sum = F1^2 + 2 F1 F2 cos T + F2^2
so
F = sqrt (F1^2 + 2 F1 F2 cos T + F2^2)
and
m = F/a
=(1/a)sqrt(F1^2 + 2 F1 F2 cos T + F2^2)
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